Science, asked by chaitaly1, 9 months ago

Question 1.13: Explain how much portion of an atom located at (i) corner and (ii) body−centre of a cubic unit cell is part of its neighboring unit cell.

Answers

Answered by UMANG75878
3

Answer

(i)the atom of corner of a cubic unit cell is shared by eight adjacent unit cells.

Therefore, portion of the atom at the corner = 8 × 1/8 = 1 atom.

(ii) The atoms present at the center of the body is not shared by its neighboring unit cell.

Therefore, portion of the atom at the center = 1 atom

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Answered by singlesitaarat31
11

 \huge { \underline{ \bf \red{HEYA\:MATE}}}]

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  • (i)the atom of corner of a cubic unit cell is shared by eight adjacent unit cells.

  • Therefore, portion of the atom at the corner = 8 × 1/8 = 1 atom.

  • (ii) The atoms present at the center of the body is not shared by its neighboring unit cell.

  • Therefore, portion of the atom at the center = 1 atom

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