Question

Question 1.25 How are 0.50 mol Na2CO3 and 0.50 M Na2CO3 different?

Class XI Some Basic Concepts of Chemistry Page 24

Answer 1

first of all we have to find ,
molar mass of Na₂CO₃ = 2 × atomic mass of Na + atomic mass of C + 3 × atomic mass of O
= 2 × 23 + 12 + 3 × 16
= 46 + 12 + 48
= 106 g/mol

now,
0.5 mole of Na₂CO₃ = 0.5 × molar mass of Na₂CO₃
= 0.5 mole × 106 g/mol
= 53 g

0.5 M of Na₂CO₃ , means 0.5 mole of Na₂CO₃ in 1 L of solution .e.g., 0.5 M of Na₂CO₃ means 53 g of Na₂CO₃ is present in 1L of the solution.

Answer 2

Answer:

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Explanation:

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