Physics, asked by BrainlyHelper, 1 year ago

Question 1.29: A hollow charged conductor has a tiny hole cut into its surface. Show that the electric field in the hole is , where is the unit vector in the outward normal direction, and is the surface charge density near the hole.

Class 12 - Physics - Electric Charges And Fields Electric Charges And Fields Page-49

Answers

Answered by abhi178
24
we know one thing that inside the conductor , the electric field is zero. and also we know a uniformly charged flat surface provide an electric field \frac{\sigma}{2\epsilon_0} normal to its plane as shown in figure.

now, if we consider a small flat part on the surface of charged conductor , it certainly provides an electric field \frac{\sigma}{2\epsilon_0} inside the conductor, which is nullified by an equal field due to rest of charged conductor.

now if a hole is made in charged conductor, the electric field due to flat part is absent but the field due to rest part of charged conductor is present. which is equal to \frac{\sigma}{2\epsilon_0}\bf{n}
Attachments:
Answered by nehanazar1995
0

Answer:

I hope you understood. Have a gud day

Attachments:
Similar questions