question 1 -. 4chairs and 3tables costs2100/- where as 5 chairs and 2 tables cost 1750/-. find the cost of 1 chair and 1 table. question 2-. five years ago ,A was twice as old as B .what is the percent age of A and B
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Answered by
1
1. 4c+3t=2100
5c+2t=1750
8c+6t=4200
15c+6t=5250
7c=1050
c=150
600+3t=2100
t=500
5c+2t=1750
8c+6t=4200
15c+6t=5250
7c=1050
c=150
600+3t=2100
t=500
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sijasubbiah
Secondary SchoolMath 13+7 pts
4 chairs and 3 tables cost rs.2100 and 5 chairs and 2 tables cost rs.1750 what is the cost of a chair and a table
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Ask for details FollowReport by Noni6809 03.05.2018
Answers
Brainly User
Hey friend..!! here your answer
________________________
let the chair equal to x
table equal to y
according to question
4 x + 3 Y = 2100 ------1
5 x + 2 Y = 1750 -------2
by solving elimination method equation 1 and 2
4 x + 3 Y = 2100 × 5
5 x + 2 Y = 1750 x 4
20 X + 15 Y = 10500
20 X + 8 y = 7000
______________
7y = 3500
we get ,
y = 500
put the value of Y in equation 1
4x + 3(500) = 2100
4x + 1500 = 2100
4x = 600
x = 150
so that the cost of chair is 150 rupees and cost of table is 500
Hope it helps you!
Here is your answer,
1)Confirm your email to get notifications about answers and receive 10 points!
Brainly.in
What is your question?
sijasubbiah
Secondary SchoolMath 13+7 pts
4 chairs and 3 tables cost rs.2100 and 5 chairs and 2 tables cost rs.1750 what is the cost of a chair and a table
Advertisement
Ask for details FollowReport by Noni6809 03.05.2018
Answers
Brainly User
Hey friend..!! here your answer
________________________
let the chair equal to x
table equal to y
according to question
4 x + 3 Y = 2100 ------1
5 x + 2 Y = 1750 -------2
by solving elimination method equation 1 and 2
4 x + 3 Y = 2100 × 5
5 x + 2 Y = 1750 x 4
20 X + 15 Y = 10500
20 X + 8 y = 7000
______________
7y = 3500
we get ,
y = 500
put the value of Y in equation 1
4x + 3(500) = 2100
4x + 1500 = 2100
4x = 600
x = 150
so that the cost of chair is 150 rupees and cost of table is 500
Hope it helps you!
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