Question 1.6: Four point charges qA = 2 μC, qB = −5 μC, qC = 2 μC, and qD = −5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of the square?
Class 12 - Physics - Electric Charges And Fields Electric Charges And Fields Page-46t
Answers
Solution:
in this problem Four point charges qA = 2 µC, qB = −5 µC, qC = 2 µC, and qD = −5 µC are located at the corners of a square ABCD of side 10 cm.
Given that
A square ABCD with each side = 10 cm = 0.1 m (divide by 100 to convert cm to m )
Charge qA = 2 µC, qB = −5 µC, qC = 2 µC, and qD = −5
And 1 µC placed at the centre of the square
Draw the figure

Apply Coulomb’s law

q1 = first charge
q2 = Second charge
r = distance between both charge
ε0= permittivity of free space
We know that OA = OC hence
FOA = - FOC
FOA + FOC = 0
Similarly
FOB + FODC = 0
Similarly other forces will also cancel out to each other
FTOTAL =0
Hence sum of all forces will =0
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The given figure shows a square of side 10 cm with four charges placed at its corners.
O is the centre of the square.
Where,
(Sides) AB = BC = CD = AD = 10 cm
(Diagonals) AC = BD = cm
AO = OC = DO = OB = cm
A charge of amount 1μC is placed at point O.
Force of repulsion between charges placed at corner A and centre O is equal in magnitude but opposite in direction relative to the force of repulsion between the charges placed at corner C and centre O.
Hence, they will cancel each other.
Similarly, force of attraction between charges placed at corner B and centre O is equal in magnitude but opposite in direction relative to the force of attraction between the charges placed at corner D and centre O.
Hence, they will also cancel each other.
Therefore, net force caused by the four charges placed at the corner of the square on 1 μC charge at centre O is zero.
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