Question

Question-1
(a) Identify the nature of roots of the equation 4x² - 4x + 1 = 0. Hence find the roots of the
equation.​

Answer 1

Answer:

roots are real and equal

roots= 1/2 ,1/2

Step-by-step explanation:

$4 {x}^{2} - 4x + 1$

here

a=4

b= -4

c= 1

D (discriminate)=

$b {}^{2} - 4ac$

D=(-4)^2 - 4×4×1

=16-16

= 0

D=0 hence roots are real and equal

root =

$( - b + \sqrt{d} ) \div 2a$

and

$(- b - \sqrt{d} ) \div 2a$

so

roots = -(-4)/8 and -(-4)/8 (as D is zero root d will be 0 also)

=> root= 1/2 ,1/2