Question

QUESTION 1.
A sum of 500 rs. is in the form of denominations of rs. 10 and rs. 20. if the total number of notes are 35, find the number of notes of each denomination.

QUESTION 2.
find a number such that if 8 is subtracted from 9 times the number ,the result is 6 more than twice the number.

Answer 1

Answer 1.

let there be x notes of rs. 10

then there will be (35-x) notes of rs. 20

total value of all notes:-

(10x+20(35-x))=500rs.

=10x+20(35-x)=500

=10x+700-20x=500

=10x-20x=500-700

-10x= -200

x=20

hence,

there are 20 notes of 10rs.

and

(35-20)=15 notes of 20 rs.

________________

Answer. 2

let the number=x

According to Question,

= 9x-8=2x+6

= 9x-2x=6+8

7x=14

x=2

hence,

required number is 2.

Answer 2

Answer:

Step-by-step explanation:

1.) Let the number of Rs 5 notes be x

Hence the number of Rs 10 notes be (90 − x)

Total sum of money

= Rs 500 ∴ 5x + 10 (90 − x)

= 500 5x + 900 − 10x

= 500 − 5x

= 500 − 900 = −400

∴ x = 80 Hence there are 80 notes of Rs 5 and 10 notes of Rs 10.

2.)9X - 8 = 2X + 6

9X - 2X = 6 + 8

7X = 14

X = 14/7 =2..

Ans. The number is 2

Hope it helps you