Math, asked by BrainlyHelper, 1 year ago

"Question 1 Draw the graph of each of the following linear equations in two variables:
(i) x + y = 4
(ii) x - y = 2
(iii) y = 3x
(iv) 3 = 2x + y

Class 9 - Math - Linear Equations in Two Variables Page 74"

Answers

Answered by nikitasingh79
200

Method to draw the graph of linear equation in two variables:

 

1. Let the linear equation in two variables be ax+by+c=0

Write the linear equation and Express Y in terms of x.

Y=(-ax+c)/b......(1)

 

 

2.

Put put arbitrary value of x in equation 1 and find the corresponding values of y.

3.

Form a table by writing the value’s of y to the corresponding values of x.

 

4.

Draw the coordinates axes on graph paper and take a suitable scale to plot points from the table on graph paper.

5.

Join the points and we get a straight line and produced it on both sides.

 

Hence, the straight line so obtained is the required graph of given linear equation.

 

It is enough to plot two points Corresponding to two solutions and join them by a line.

 

 ----------------------------------------------------------------------------------------------------

[ Table & graph are in the attachment]

Solution:

i)

Given Equation is

x +y= 4

 

To draw the graph we need at least 2 solutions of the equation.

Given equation can be written as

Y=4-x

When x=0, then y=4

When x=4, then y=0

 

So, plot the points

A(0,4), B(4,0) on the graph paper and join them by line.

 

Hence, line AB represents the required graph of a linear equation.

 

 ii)

x-y=2

-y=2-x

y=x-2

when x=0, then y= -2

when y=0 , then x=2


iii) y=3x

when x=0, then y=0

when y=3, then x=1


iv)

3=2x+y

2x+y-3=0

y=(-2x+3) 

when x= 0, then y=3

when x=1, then y=1

=========================================================

Hope this will help you.....

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Answered by 27Tushar
52

Answer:

Step-by-step explanation:

Method to draw the graph of linear equation in

two variables:

 

1. Let the linear equation in two variables be ax+by+c=0

Write the linear equation and Express Y in terms

of x.

Y=(-ax+c)/b......(1)

 

 

2.

Put put arbitrary value of x in equation 1 and

find the corresponding values of y.

3.

Form a table by writing the value’s of y to the

corresponding values of x.

 

4.

Draw the coordinates axes on graph paper and take

a suitable scale to plot points from the table on graph paper.

5.

Join the points and we get a straight line and

produced it on both sides.

 

Hence, the straight line so obtained is the

required graph of given linear equation.

 

It is enough to plot two points Corresponding to

two solutions and join them by a line.

 

 ----------------------------------------------------------------------------------------------------

[ Table & graph are in the attachment]

Solution:

i)

Given Equation is

x +y= 4

 

To draw the graph we need at least 2 solutions of

the equation.

Given equation can be written as

Y=4-x

When x=0, then y=4

When x=4, then y=0

 

So, plot the points

A(0,4), B(4,0) on the graph paper and join them

by line.

 

Hence, line AB represents the required graph of a

linear equation.

 

 ii)

x-y=2

-y=2-x

y=x-2

when x=0, then y= -2

when y=0 , then x=2

iii) y=3x

when x=0, then y=0

when y=3, then x=1

iv)

3=2x+y

2x+y-3=0

y=(-2x+3) 

when x= 0, then y=3

when x=1, then y=1

=========================================================

Hope this will help you.....

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