Math, asked by shauryaamalhotra, 6 months ago

Question 1
Factorize the following expression
a) x(1 - b)-y(1 - b)
b) 9r(z + 1) + 3r(z+ 1)
c) p + q? + 5a(p’ + q?)
d) x + xy + 8x + 8y
e) B(x + y) -9(x + y)
() (3m-7n) - n(3m-7n)
g) (2m-5) (3a - 2b) - (2m-5) (2b-3a)
h) x( 1 + y) + (7 + 7y)
D (6xy + 3x) + (2y + 1)
3) X(y – z)-az-y)
k 2-7 + 7 xy-xyz
Question 2
Factorize the following expressions.
z + 6z +8
(ii) z - 10z + 21
Giff) 2 + 62 – 16​

Answers

Answered by ahanatarafder06
28

Answer:

Question 1 : Factorize the following expression.

a) x(1 - b)-y(1 - b)

= (1-b)(x-y)

b) 9r(z + 1) + 3r(z+ 1)

= (z+1)(9r+3r)

= (z+1)(12r)

c) p + q + 5a(p + q)

= 1(p+q)+5a(p+q)

= (p+q)(1+5a)

d) + xy + 8x + 8y

= x(x+y)8(x+y)

= (x+y)(x+8)

e) B(x + y) -9(x + y)

= (x+y)(B-9)

(f) (3m-7n) - n(3m-7n)

= (3m-7n)(1-n)

g) (2m-5) (3a - 2b) - (2m-5) (2b-3a)

= (2m-5)(3a-2b-(2b-3a))

= (2m-5)(3a-2b-2b+3a)

= (2m-5)(6a-4b)

h) x( 1 + y) + (7 + 7y)

= x(1+y)+7(1+y)

= (1+y)(x+7)

(i) (6xy + 3x) + (2y + 1)

= 3x(2y+1)+1(2y+1)

= (2y+1)(3x+1)

Question 2: Factorize the following expressions.

I) + 6z +8

= +4z+2z+8

= z(z+4)+2(z+4)

= (z+4)(z+2)

(ii) - 10z + 21

= -7z-3z+21

= z(z-7)-3(z-7)

= (z-7)(z-3)

Similar questions