Question

Question-1
Find the height of a parallelogram whose area is 54cm² and the base is 15cm.

Question-2
The base of a parallelogram is twice its height. If the area of the parallelogram is 512cm².
Find the base and the height.

Question-3
Find the area of a rhombus,the length of whose diagonals are:
1) 16cm and 28cm
2) 8dm,5cm and 5dm,6cm​

Answer 1

Answer 1 :

GiveN -

• Area of a parallelogram = 54cm².
• Base of a parallelogram = 15 cm.

FinD -

• Height of the parallelogram = ?

SolutioN -

Area of the parallelogram = Base × height

54cm² = 15cm × height

height = 54/15 = 3.6 cm

Answer 2 :

Let, height = x cm.

base = 2x cm.

Area of the parallelogram = 512cm² .

Area of a parallelogram = Base x Height 512 = (2x) × (x)

512 = 2x²

= 512/2 = 256 cm²

= (16)2 x = 16 cm

Hence height of parallelogram

= x = 16 cm

base of the parallelogram

= 2x = 2 x 16 = 32

Answer 3 :

(i) Area of the rhombus = $\sf \: \frac{d_1 \times d_2}{2}$

Diagonal 1 = 16 cm

Diagonal 2 = 28 cm

= 16 × 28/2

= 224 cm

(ii) Area of the rhombus = $\sf \: \frac{d_1 \times d_2}{2}$

= 1/2 d1 × d2

= 5 × 6/2

=30/2 = 15 cm