Question

Question 1
For some integer m, every even integer is of
the form
A) m
B) m + 1
C) 2m
D) 2m + 1
​

Answer 1

Answer:

B..................

Answer 2

Answer:

Step-by-step explanation:any integer=a

Divisor= 2 a= 2q+r

Possible reminders= 0,1

Possible integers=a=2m+0

2m+1

If r=0

Our equation becomes

a=2m+0

If r=1

Our equation becomes

a=2m+1