Question

Question 1

For the circuit above, R = 4\text{M}\OmegaR=4MΩ and C = 0.75\mu\text{F}C=0.75μF. v_i(t) = -t ^2\text{V}v
i
​
(t)=−t
2
V for 0 \text{s} \leq t \leq 5\text{s}0s≤t≤5s. What is the value of v_ov
o
​
at time t=5\text{s}t=5s, if v_o(0)=0v
o
​
(0)=0?

Answer 1

Answer:

The new acceleration is 12 m/s²

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➤ How to solve ?

A Force is a push / pull upon an object resulting from the people interaction with any of the another object.

Newton's 2nd law stated as F = Ma

Means,

•F acting on an object is equal

⠀⠀⠀⠀⠀to the mass of an object time it's A.

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➤ Solution :

As , F = ma

➨ a = F / m

➨ 2 = F / m

Now , we want to see the value of a produced with 3f respectively

➨ a = F / m

➨ a = F / m/ ²

➨ a = 6 F / m

As we have already got F / m = 2

➨ 1 / 6 a = 2

➨ a = 12 m/s ²

⁖ New Acceleration is 12 m/s ²

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