Question

Question. 1 : In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm.

Answer 1

Step-by-step explanation:

$ac = \sqrt{ {ab}^{2} + {bc}^{2} }$

$ac = \sqrt{576 + 49} = \sqrt{625}$

$ac = 25$

Answer 2

Answer:

In Δ ABC, B is at right angle.

Given, AB=24cm

BC=7cm

using Pythagoras theorem

AB2+BC2=AC2

⇒(24)2+(7)2=AC2

​=AC=root576+49

​=root625

​

⇒AC=25CM

(i)sin A=AC/BC​

=25/7​

cos A=AC/AB​

=25/24​

(ii)sin C=AC/AB​

=25/24​

cos c=AC/BC​

=25/7​  

Step-by-step explanation: