Math, asked by rahmanzoya237, 8 days ago

Question. 1 : In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm.
Determine:
(i) sin A, cos A

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Answers

Answered by Anonymous
1

Answer:

Solution

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In Δ ABC, B is at right angle.

Given, AB=24cm

BC=7cm

using Pythagoras theorem

AB

2

+BC

2

=AC

2

⇒(24)

2

+(7)

2

=AC

2

⇒AC=

(24

2

)+(7)

2

=

576+49

=

625

⇒AC=25CM

(i)sin A=

AC

BC

=

25

7

cos A=

AC

AB

=

25

24

(ii)sin C=

AC

AB

=

25

24

cos c=

AC

BC

=

25

7

Step-by-step explanation:

hope it help you army

Answered by affumunnagunda
2

Answer:

sin A =

 \frac{7}{25}

cos A=

 \frac{24}{25}

Hope it's helpful

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