Question

Question 1. In the adjoining figure, PA and PB are tangents from point P to a circle with centre O. If the radius of the circle is 5 cm and PA⊥PB then the length OP is equal to *
1 point
Captionless Image
5 cm
10 cm
7.5 cm
5√2​

Answer 1

Answer:

From figure,

CA is perpendicular to AP and CB is perpendicular to BP

Again AC = BC = 4 (radius of the circle)

Also AP = PB = (Tangents from point P)

So, BPAC is a square.

=> AP = PB = BC = CA = 4 cm

So, length of tangents are 4 cm each

therefore option B will be the answer.

solution

Answer 2

Answer:

This question can be solved by trignometry

Ans (a) 5 cm

Step-by-step explanation:

angle OPA = 45°

tan45° = PA/OP=PA/5

1=PA/5

PA = 5 Ans