Question: 1 In the attachment.!
Question 2:
Construct a quadrilateral BARC such that
length (BA) = length (BC) = 4.2cm
length(AC)=6.0cm ,
length(AR) = length (CR) = 5.6cm
_________
Solve it friends!☺
____
Answers
Steps of Construction:
Step 1: Draw AB = 3 cm.
Step 2: Draw ZABX = 40°.
Step 3: With B as centre and radius 7 cm, draw an arc cutting the ray BX at C.
Step 4: With C as centre and radius 3 cm, draw an arc.
Step 5: With A as centre and radius 7 cm, draw an
arc cutting the previous arc at D.
Step 6: Join AD and CD.
Here, ABCD is the required parallelogram.
Steps of Construction:
Step 1: Draw BA = 4.2 cm.
Step 2: With B as centre and radius
4.2 cm, draw an arc.
Step 3: With A as centre and radius 6 cm, draw an arc cutting the previous arc at C.
Step 4: Join BC.
Step 5: With A as centre and radius 5.6 cm, draw an arc.
Step 6: With C as centre and radius 5.6 cm, draw an arc cutting the previous arc at R.
Step 7: Join AR and CR.
Here, BARC is the required quadrilateral.
[ NOTE-REFER TO THE ATTACHMENTS ]
Answer:
number 1 ;
Steps of Construction:
Step 1: Draw AB = 3 cm.
Step 2: Draw ZABX = 40°.
Step 3: With B as centre and radius 7 cm, draw an arc cutting the ray BX at C.
Step 4: With C as centre and radius 3 cm, draw an arc.
Step 5: With A as centre and radius 7 cm, draw an
arc cutting the previous arc at D.
Step 6: Join AD and CD.
Here, ABCD is the required parallelogram
number 2;
steps of construction
Step 1: Draw BA = 4.2 cm.
Step 2: With B as centre and radius
4.2 cm, draw an arc.
Step 3: With A as centre and radius 6 cm, draw an arc cutting the previous arc at C.
Step 4: Join BC.
Step 5: With A as centre and radius 5.6 cm, draw an arc.
Step 6: With C as centre and radius 5.6 cm, draw an arc cutting the previous arc at R.
Step 7: Join AR and CR.
Here, BARC is the required quadrilateral.
hopefully it will work ☺️☺️☺️