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A box contains 5 green, 3 red and 4 black pens. If 2 pens are drawn at random from the box, not replaced and then another pen is drawn. What
is the probability of drawing 2 green pens and 1 black pen?
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Probability of drawing 2 green pens = 2/10 = 1/5
Probability of drawing 1 black pen = 1/10
Remember:
Total number of pens are 12 (5 green+ 3 red+ 4 black)
But since we have removed 2 pens and not replaced them, total number of pens now will be 10!
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