Question

question 1 plzzzz....​

Answer 1

HELLO DEAR FRIEND

STEP BY STEP EXPLANATION
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GIVEN EQUATION

$\large{(k - 1) { x}^{2} + kx + 1}$

GIVEN ONE ZERO = - 3

PUTTING THE VALUE OF X AS - 3

$\large{(k - 1) { (- 3)}^{2} + ( - 3)k + 1} = 0$

$\large{9(k - 1) - 3k \: + 1} = 0$

$\large{9k - 9 - 3k \: + 1} = 0$

$\large{6k -8} = 0$

$\large{6k = 8}$

$\large{k = \frac{ \large{8}}{ \large{6}} }$

$\large{k = \frac{ \large{4}}{ \large{3}} }$

Answer 2

The given equation is (k-1) x2 +kx + 1 = 0

put -3 in equation

(k-1) (-3)2 + k(-3) + 1 = 0

9k - 9 -3k + 1 = 0

6k - 8 = 0

6k = 8

k = 8/6

k = 4/3