question 1 quick plzzzz
Attachments:
Answers
Answered by
0
Given that, a =x3y2 = x × x × x × y × y
and b = xy3 = x × y × y × y
∴ HCF of a and b = HCF (x3y2,xy3) = x × y × y = xy2
[Since, HCF is the product of the smallest power of each common prime factor involved in the numbers]
and b = xy3 = x × y × y × y
∴ HCF of a and b = HCF (x3y2,xy3) = x × y × y = xy2
[Since, HCF is the product of the smallest power of each common prime factor involved in the numbers]
Similar questions