Question

# Question 1 - Rahul pushed a toy car it moved the distance of 50 m . If the work done by Rahul is 1500 J . How much force did you apply through the push ?

# Question 2 - Find the work done if a force of 1000 N is applied on a load and it moves a distance of 50 cm .

# Question 3 - If the work done by pushing a trolley by applying 850 N and is 1275 J find the distance the trolley moves

# Question 4 - Prem starts from position A and pushes a pram for 2 m in the east , then turns towards the north and pushes it through a distance of 3.5 m . He then pushes the pram to some distance to return to point A if he applies a force of 5n calculate the work done by him

# Question 5 - A worker does 150 J of work by the force of 60 N find the displacement .​

Answer 1

1. f300n
2. The impulse-momentum theorem seems applicable to this situation. Force was applied to a body at rest and after 5 seconds it covered a distance of 1000 cm or 10 m. The formula is Δp = F * Δt where Δp is the change in momentum, F is the applied force and Δt is the elapsed time. Rearranging, the formula becomes F = Δp / Δt. Since Δp = m * Δv, then F = (m * Δv) / Δt. Plugging-in the given values, F = (50 kg * 4 m/s) / 5 s.
3. The computed value of the force F is 40 N.
4. Another method is to use F = ma but a has to be computed first using (v2^2 - v1^2) = 2 * a * d where a is the acceleration, v2 is the final velocity, v1 is the initial velocity and d is the distance covered. The given values are v1 = 0 m/s, d = 10 m, a = ? , v2 = ?. There are two unknown values but v2 can be calculated first using d = average speed / time.
5. Avg speed = 10 m / 5 s
6. Avg speed = 2 m / s
7. Final speed = 4 m/s
8. Computing for the acceleration a
9. (v2^2 - v1^2) = 2 * a * d
10. a = (v2^2 - v1^2) / 2d
11. a = (4^2 - 0^2) / 2 * 10
12. a = 16 / 20
13. a = 0.8 m/s^2
14. Computing for the force F
15. F = ma
16. F = 50 * 0.8
17. F = 40 N
18. The computed value of the force F is 40 N.
19. We have:
20. Force (F) = 50N
21. Displacement (s) = 5m.
22. As we know, we calculate work as:
23. Work = Force * Displacement in direction of Force,
24. W=F⋅s,
25. W=50⋅5,
26. W=250Nm. So,
27. The work done is 250Nm (Newton meters).
28. sorry
29. sorry

Answer 2

Answer:

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