Question 1
Read the extract given below and answer the questions that follow:
[10]
I go in the rain, and, more than needs,
A rope cuts both my wrists behind;
And I think, by the feel, my forehead bleeds,
For they fling, whoever has a mind,
Stones at me for my year's misdeeds.
(i) Who is the speaker? Where is he being taken to? What do the people do
while the speaker is being taken to his destination?
[3]
(ii) Give two examples each, to indicate the change in people's attitude towards
the speaker before and now. What does this indicate about the people?
[3]
(iii) How does the speaker enter and leave from people's life? Who does the
speaker have faith in? Why?
[4]
PLS REPLY FASTTT
Answers
Answer:
♣ Given:−
\begin{gathered} \sf{2A + 2B = \left[\begin{array}{cc}2& - 1& 4 \\3 & 2 & 5\end{array}\right] } \\ \\ \sf{A + 2B = \left[\begin{array}{cc}5 & 0 & 3 \\1 & 6 & 2 \end{array}\right]}\end{gathered}
2A+2B=[
2
3
−1
2
4
5
]
A+2B=[
5
1
0
6
3
2
]
-----------------------
\large \bf \clubs \: To \: Find :-♣ ToFind:−
Value of 2B .
-----------------------
\large \bf \clubs \: Solution:-♣ Solution:−
We Have,
\begin{gathered} \pmb{2A + 2B = \left[\begin{array}{cc}2& - 1& 4 \\3 & 2 & 5\end{array}\right] } \: \: - - - - (1)\\ \\ \: \: \: \: \:\pmb{A + 2B = \left[\begin{array}{cc}5 & 0 & 3 \\1 & 6 & 2 \end{array}\right]} \: \: - - - - (2)\end{gathered}
2A+2B=[
2
3
−1
2
4
5
]
2A+2B=[
2
3
−1
2
4
5
] − − − −(1)
A+2B=[
5
1
0
6
3
2
]
A+2B=[
5
1
0
6
3
2
] − − − −(2)
Multiplying Eq. (2) by 2 We Get :
\begin{gathered} \pmb{2A + 4B = \left[\begin{array}{cc}10 & 0 & 6 \\2 & 12 & 4\end{array}\right]} \: \: - - - - (3)\end{gathered}
2A+4B=[
10
2
0
12
6
4
]
2A+4B=[
10
2
0
12
6
4
] − − − −(3)
Subtracting (1) From (3) We Get :
\begin{gathered} \sf \cancel{2A} + 4B - \cancel{2A} -2B \\ = \left[\begin{array}{cc}10 & 0 & 6 \\ 2 & 12 & 4\end{array}\right] - \left[\begin{array}{cc}2 & - 1 & 4 \\3 & 2 & 5\end{array}\right] \\ \\ :\longmapsto\sf2B = \left[\begin{array}{cc} 10- 2& 0+ 1& 6- 4 \\ 2- 3 & 12- 2 & 4 - 5\end{array}\right] \\ \\ \end{gathered}
2A
+4B−
2A
−2B
=[
10
2
0
12
6
4
]−[
2
3
−1
2
4
5
]
:⟼2B=[
10−2
2−3
0+1
12−2
6− 4
4−5
]
\begin{gathered}\purple{ \large :\longmapsto \pmb{ \underline {\boxed{{2B = \left[\begin{array}{cc} 8& 1& 2 \\ - 1 & 10 & - 1\end{array}\right]} }}}}\end{gathered}
:⟼
2B=[
8
−1
1
10
2
−1
]
2B=[
8
−1
1
10
2
−1
]
\underline{\underline{\Large\pink{\mathfrak{ \text{H}ence \:\:option\:\: B\:\: Correct} }}}
HenceoptionBCorrect
\begin{gathered} \Large\red{\mathfrak{ \text{W}hich \:\:is\:\: the\:\: required} }\\ \LARGE \red{\mathfrak{ \text{ A}nswer.}}\end{gathered}
Whichistherequired
Answer.
-----------------------
♣ Given:−
\begin{gathered} \sf{2A + 2B = \left[\begin{array}{cc}2& - 1& 4 \\3 & 2 & 5\end{array}\right] } \\ \\ \sf{A + 2B = \left[\begin{array}{cc}5 & 0 & 3 \\1 & 6 & 2 \end{array}\right]}\end{gathered}
2A+2B=[
2
3
−1
2
4
5
]
A+2B=[
5
1
0
6
3
2
]
-----------------------
\large \bf \clubs \: To \: Find :-♣ ToFind:−
Value of 2B .
-----------------------
\large \bf \clubs \: Solution:-♣ Solution:−
We Have,
\begin{gathered} \pmb{2A + 2B = \left[\begin{array}{cc}2& - 1& 4 \\3 & 2 & 5\end{array}\right] } \: \: - - - - (1)\\ \\ \: \: \: \: \:\pmb{A + 2B = \left[\begin{array}{cc}5 & 0 & 3 \\1 & 6 & 2 \end{array}\right]} \: \: - - - - (2)\end{gathered}
2A+2B=[
2
3
−1
2
4
5
]
2A+2B=[
2
3
−1
2
4
5
] − − − −(1)
A+2B=[
5
1
0
6
3
2
]
A+2B=[
5
1
0
6
3
2
] − − − −(2)
Multiplying Eq. (2) by 2 We Get :
\begin{gathered} \pmb{2A + 4B = \left[\begin{array}{cc}10 & 0 & 6 \\2 & 12 & 4\end{array}\right]} \: \: - - - - (3)\end{gathered}
2A+4B=[
10
2
0
12
6
4
]
2A+4B=[
10
2
0
12
6
4
] − − − −(3)
Subtracting (1) From (3) We Get :
\begin{gathered} \sf \cancel{2A} + 4B - \cancel{2A} -2B \\ = \left[\begin{array}{cc}10 & 0 & 6 \\ 2 & 12 & 4\end{array}\right] - \left[\begin{array}{cc}2 & - 1 & 4 \\3 & 2 & 5\end{array}\right] \\ \\ :\longmapsto\sf2B = \left[\begin{array}{cc} 10- 2& 0+ 1& 6- 4 \\ 2- 3 & 12- 2 & 4 - 5\end{array}\right] \\ \\ \end{gathered}
2A
+4B−
2A
−2B
=[
10
2
0
12
6
4
]−[
2
3
−1
2
4
5
]
:⟼2B=[
10−2
2−3
0+1
12−2
6− 4
4−5
]
\begin{gathered}\purple{ \large :\longmapsto \pmb{ \underline {\boxed{{2B = \left[\begin{array}{cc} 8& 1& 2 \\ - 1 & 10 & - 1\end{array}\right]} }}}}\end{gathered}
:⟼
2B=[
8
−1
1
10
2
−1
]
2B=[
8
−1
1
10
2
−1
]
\underline{\underline{\Large\pink{\mathfrak{ \text{H}ence \:\:option\:\: B\:\: Correct} }}}
HenceoptionBCorrect
\begin{gathered} \Large\red{\mathfrak{ \text{W}hich \:\:is\:\: the\:\: required} }\\ \LARGE \red{\mathfrak{ \text{ A}nswer.}}\end{gathered}
Whichistherequired
Answer.