Question 1. solve : 3t − 23 + 2t + 3 2 = t +76 Question 2. 4t - 3 + ( 3t = 1 ) = 5t - 4 Question 3. Divide 54 into two parts such that one part is 27 of others.
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Answered by
1
Answer:
q-1) 3t +2t-1t = 76 - 32 + 23
4t = 67
t = 67/4
t = 16.75
q-2) -3 +4 = 5t - 4t
1 = t
t = 1
q-3) 9,36
36-9=27
1st number be 9
2nd number be 36
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Answered by
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Step-by-step explanation:
1. 3t − 23 + 2t + 3 2 = t +76
3t+2t–t= 76–32+26
4t = 70
t = 17.5
_____________________
2. 4t - 3 + ( 3t –1 ) = 5t - 4
4t –3 + 3t –1 = 5t–4
4t +3t –5t = –4+3+1
2t = 0
t = 0/2
t = 0
______________________
3. Let one part of 54 be x.
∴x+ 2/7x = 9/7x ⟹54
x=42
2/7 x=12
The numbers are 42,12
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