Question:
(1)..The body of mass 100kg moving with acceleration 5m/s^2 then find the force?
I need correct explanation of this question of physics
plzz........ don't give any irrelevant answers otherwise i will block them who give here any irrelevant answer
Answers
Answer:
Consider the problem
Given,
The mass of the vehicle m=100kg
The initial velocity u=5m/s.
The time required to stop the vehicle t=
10
1
sec i.e 0.1second.
The final velocity of the vehicle v=0m/s.
As per Newton's second law of motion, we know that force is equal to rate of change of momentum.
F=
dt
dp
Here F and p stands for force and momentum
=m
t
v−u
=100
0.1
[0−5]
N
=−5000N
The Negative sign indicates the force is in opposite direction
Therefore, F=5000N
Hence, Option C is the correct answer.
Mass of the body (m) = 100 kg
Acceleration (a) = 5 m/s²
Force applied (F) = ?
We know F = ma
(just put the given values for the amount of force applied on that body)...
F = 100 × 5
F = 500 N
The force is 500 Newton.
_____________________________
Let's learn how to derive the formula of force !
Newton's 2nd law of motion states that the rate of change of momentum is directly proportional to the force pplied and takes place in direction of force.
So, we know that Force is directly proportional to change in momentum/time
There is a rule tha if we remove that proportionality sign we have to put a constant.
Force = k × Change in momentum/time (here, k is constant)
The value of constant k is 1.
F = mv - mu/t
F = m(v-u)/t
We know, a = v - u/t
F = ma
And we are done !
Hope it helped you dear...