Physics, asked by banza8089tow, 1 year ago

QUESTION 1

The "Compton effect" showed (3 points)


that light undergoes interference


how an experiment can mislead


the wave nature of light


the particle nature of light

3 points

QUESTION 2

Wave interference (3 points)


is a property of light


occurs when light and water interact


is a property of all waves

3 points

QUESTION 3

Light demonstrates the characteristics of (3 points)


particles only


waves only


both particles and waves


neither particles nor waves

3 points

QUESTION 4

A photon (3 points)


is a quantum of light


is a wave


means kinetic energy

3 points

QUESTION 5
Using Planck's constant as h = 6.63 E-34 J*s, what is the wavelength of a proton with a speed of 5.00 E6 m/s? The mass of a proton is 1.66 E-27 kg.
Remember to identify your data, show your work, and report the answer using the correct number of significant digits and units. (5 points)

Answers

Answered by shivendramishra872
0
I didn't understand the question

shivendramishra872: sorry brother I can't understand the question
Answered by sargamkashyap
8
☯️ANSWER 1.
I would say the particle nature of light. 

It showed how there is a decrease in the energy of a photon when it interacts with matter. 

This sounds to me like conservation of momentum.

☯️ANSWER 2.
interference is a phenomenon in which two wavessuperpose to form a resultantwave of greater, lower, or the same amplitude. ... Interferenceeffects can be observed with alltypes of waves, for example, light, radio, acoustic, surface water waves, gravity waves, or matterwaves...

☯️ANSWER 3.
I believe it is both particles and waves, light is considered particle stored with energy that create light, which is a type of wave as well.

☯️ANSWER 4.
A quantum of light of wavelength is the minimum amount of energywhich can be stored in an electromagnetic wave at that wavelength, which is Planck's constant h times the frequency.

☯️ANSWER 5.
We can solve the problem by using De Broglie's relationship:
p= mv= \frac{h}{\lambda}p=mv=λh​ 
where
p is the momentum of the particle
m is the the mass
v is the velocity
h is the Planck constant
\lambdaλ is the wavelength of the particle

By re-arranging the equation, we get
\lambda = \frac{h}{mv}λ=mvh​ 
and by using the data about the proton mass and speed, we find its wavelength:
\lambda= \frac{6.6 \cdot 10^{-34} Js}{(1.66 \cdot 10^{-27} kg)(5.0 \cdot 10^6 m/s)}=7.95 \cdot 10^{-14} mλ=(1.66⋅10−27kg)(5.0⋅106m/s)6.6⋅10−34Js​=7.95⋅10−14m

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