Math, asked by khanmatin1020, 1 month ago

Question 1 - The diameter of a roller
is 42 cm and its length is 150 cm. It
takes 200 complete revolutions to
move once over to level a playground.
Find the area of the playground in
meter square​

Answers

Answered by abhayvermaxp9t6
0

Answer:

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Answered by sundarshyam1975
0

Answer:

729m^2

Step-by-step explanation:

We have the diameter of a cyclindrial roller = 42 cm

⇒ The radius of cyclindrical roller (r) = 42 / 2 = 21 cm

Length of a cyclindrical roller (h) = 120 cm 

Curved surface of roller = 2πrh = 2 × 22 / 7 × 21 × 120=

15840 cm2 

= 15840 / 10000 m2 = 1.584 m2 

Area covered by the roller in one complete revolution . 

= curved surface of the roller = 1.584 m2

∴ Area of the playground = Area covered by the roller in

500 complete revolutions  

= 500 × 1.584

= 792 m2 

I think it's help you....

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