Math, asked by maahira17, 1 year ago

"Question 1 There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

Class 8 Mensuration Page 186"

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Answered by nikitasingh79
94

Mensuration:

Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.

Surface area:

The surface area of a solid is the sum of the areas of the plane or curved faces of the solid.

It is measured in square units such as square centimetre (cm²) and square metre (m²).

Surface area of cuboid or cube is the sum of the surface areas of its six rectangular  faces.

Surface Area of Cuboid is =
2(lb + lh + bh)

By surface area of a cuboid or cube  we mean the total surface area.


Total surface area of a cube= 6a²


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Solution:

Given:

 Length of cuboidal box(l)  = 60 cm

Breadth of cuboidal box (b) = 40 cm

Height of cuboidal box(h)= 50 cm

 Total surface area of cuboidal box= 2(lb+bh+hl)

= 2 (60 × 40 + 40 × 50 + 50× 60)

= 2 (2400 + 2000 + 3000)

= 2  × 7400

= 14800 cm²

  Total surface area of cuboidal box= 14800 cm²



(b) Given:

Side of a cube (a) = 50

Total surface area of a cube= 6a²

Total surface area of a cube=6× (50)²

= 6 × 2500

= 1500 m²

 Total surface area of a cube=1500 m²

Hence cuboidal box (a)  requires the lesser amount of material to make.

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Hope this will help you..

Answered by jayGkcvvv
45
Hlo mahira this is the answer
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