Question

Question-1 Three consecutive integer are such that when they are taken in increasing order and multiplied by 2 ,3 and 4 respectively they add up to 74 find these numbers​

Answer 1

Step-by-step explanation:

let

1st consecutive no. be n

2nd consecutive no be n+1

and 3rd consecutive be n+2

n*2+(n+1)3+(n+2)4=74

2n +3n+3+4n+8=74

9n+11=74

9n=74-11

9n=63

n=7

thus 1st no. =7

2nd no is 8

3rd no. is 9

Answer 2

Answer:

n = 7

Step-by-step explanation:

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