Question

Question 1

Three consecutive integers are as such when they are taken in increasing

order and multiplied by 2, 3, and 4 respectively, they add up to 56. Find

these numbers.Question 1

Three consecutive integers are as such when they are taken in increasing

order and multiplied by 2, 3, and 4 respectively, they add up to 56. Find

these numbers.​

Answer 1

Answer:

The three consecutive numbers are 5, 6 and 7 respectively.

Step-by-step explanation:

Given:

• Three consecutive integers are as such when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 56.

To find:

• The three consecutive numbers.

Solution:

Let the three consecutive numbers are n, n + 1 and n + 2 respectively.

( They are in increasing order )

Now,

They are multiplied by 2, 3 and 4 respectively and then they add up to 56 means their sum is equal to 46. Thus forming an adequate equation and doing the required calculations, we will find out the three consecutive numbers.

Let's find out...

According to the problem,

• 2n + 3( n + 1 ) + 4( n + 2 ) = 56
• 2n + 3n + 3 + 4n + 8 = 56
• 5n + 3 + 4n + 8 = 56
• 9n + 3 + 8 = 56
• 9n + 11 = 56
• 9n = 56 - 11
• 9n = 45
• n = 45/9
• n = 5

Now, find out the numbers.

First number

• n = 5

Second number:

• n + 1
• 5 + 1
• 6

Third number

• n + 2
• 5 + 2
• 7

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