Question

Question 10
[3]
The mass string system shown in the figure is in equilibrium. The mass of block A is
1 kg and block B is 0.2 kg. If the coefficient of friction between block A and the table
is 0.3, find the frictional force on the block A. [g=9.8 m/s²] ​

Answer 1

Answer:

Limiting value of frictional force,

f

max

=μN=.5×5=2.5N

Now, value of mg=0.1×9.8=0.98N

f

max

>mg

then frictional force acting on block is

f=mg=0.98N

Step-by-step explanation:

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