Question

Question 10. A wire has a diameter of 0.5 mm and a resistivity of 1.6 x 10-622 cm. How much of this
wire would be required to make a 10 12 coil?​

Answer 1

Answer:

Given, Diameter=0.5mm,resistivity=1.6×10

−8

Ω−m,resistance=10Ω

we know that R=ρ

A

1

⇒1=

ρ

RA

Where A is the area of the cross-section,

=

1.6×10

−8

10×3.14×(

2

0.0005

)

2

=122.7m

Thus the length of the wire is 122.7m