Question

Question 10(b) please

Answer 1

Heya...here is ur answer
well A.T.Q.,
let radii of three circles be x , y and z
so,
x+y=10---(1)
y+z=8---(2)
z+x=6---(3)
now, x=10-y
y=8-z
putting value of x in (3)
z+(10-y)=6---(4)
putting value of y in (4)
z+10-(8-z)=6
z+10-8+z=6
2z+2=6
2(z+1)=6
z+1=3
z=2
................
now, we know
y=8-z
y=8-2.....(z=2)
y=6
and,
x=10-y
x=10-6.....(y=6)
x=4
................
therefore, the radii be
x=4
y=6
z=2
......
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