Question

Question 10.
Each of the two point charges are doubled
and their distance is halved. Force of
interaction becomes p times, where p is:
(a) 1
(b) 4.
(C)
(d) 16
16

Answer 1

Answer:

c 16

Explanation:

By Coulomb's law, the force between two charges q

1

and q

2

is F=

r

2

kq

1

q

2

where r= separation between charges.

When charges are doubled and their distance is halved , the force of interaction becomes F

′

=

(r/2)

2

k(2q

1

)(2q

2

)

=16F

Thus, the value of n will be 16.