Question

Question: 10
If α and β are the zeroes of the quadratic polynomial

f(t) = t2 – 4t + 3, find the value of α4β3 + α3β4.
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Answer 1

Answer:

Step-by-step explanation:

First of all:

f(t)=t(2sq.)-4t+3.

=t(2sq.)-t-3t+3

=t(t-1)-3(t-1)

=(t-3)(t-1)

So,

The zeros are 3,1.

alpha:3

beta:1

now,

a(4powered.)xB(3powered)+a(3powered)xB(4 powered)

={(3x3x3x3)(1x1x1)}+{(3x3x3)(1x1x1x1)}

=( 81x1) +(27+1)

=81+27

=108

HOPE IT WILL HELP YOU YOU

Answer 2

Solution:

Since, α and β are the zeroes of the quadratic polynomial f(t) = t2 – 4t + 3

So, Sum of the zeroes = α + β = 4

Product of the zeroes = α × β = 3

Now,

α4β3 + α3β4 = α3β3(α + β)

= (3)3(4) = 108