Question

Question 10
in the figure below, ABCE is a right-angled triangle. F is the midpoint of BE and D is a point on CE. FD is produced
by its own length to G and forms parallelogram BCGF. FD = 30 mm and DE = 25 mm
10.1
Why is ED = DC
E
10.2
Prove that EFCG is a rhombus
D
.
B
С
4 GR (niapt them)​

Answer 1

Answer:

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