Question 10
Let P(E) denote the probability of an event E happen-
ing. In an experiment, there are 4 possible outcomes
such that each of them are probable with distinct
probability. Each probability is a decimal number
0.CO, O.RO, O.NA and 0.19 where C,O,R,N and A
represent digits. If each of the first three probabilities
consist of the digit 5, find value of C (Given C>R).
Answers
Given : 4 possible outcomes such that each of them are probable with distinct probability . Each probability is a decimal number
0.CO + 0.RO + 0.NA + 0.19 . each of the first three probabilities consist of the digit 5 C > R
To find : Value of C
Solution:
0.CO + 0.RO + 0.NA + 0.19 = 1
first three probabilities consist of the digit 5
Let say O is not 5 Then
C & R has to be 5
Then Sum of probabilities will be greater then 1 hence not possible
so O has to be 5
Now
as O = 5 then A Has to be 1 (as 5 + 5 + A + 9 should end with 0)
A is 1 hence N has to be 5
So we get
0,C5 + 0.R5 + 0.51 + 0.19 = 1
=> 0.C5 + 0.R5 = 0.3
=> 0.C + 0.R = 0.2
Possible values of C & R
are 2 & 0 as C > R
Hence Value of C = 2
Probabilities are
0.25 , 0.05 + 0.51 + 0.19
Value of C = 2
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