Question 11: Find the value of tan¯¹ [2 cos (2sin-1 1/2) ]
Class 12 - Math - Inverse Trigonometric Functions
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Answered by
41
Hey there!!!
=> tan¯¹ [2 cos (2sin^-1 1/2) ]
Let sin^-1 1/2 = x
sinx = 1/2= sin(π/6)
therefore, sin^-1 1/2 = π/6
Now,
tan¯¹ [2 cos (2sin^-1 1/2) ]
=> tan¯¹ [2 cos (2×π/6)]
=> tan¯¹ [ 2 cos π/3 ]
=> tan¯¹ [2×1/2]
=> tan¯¹ [1]
=> π/4
Hope it helps.....✌
=> tan¯¹ [2 cos (2sin^-1 1/2) ]
Let sin^-1 1/2 = x
sinx = 1/2= sin(π/6)
therefore, sin^-1 1/2 = π/6
Now,
tan¯¹ [2 cos (2sin^-1 1/2) ]
=> tan¯¹ [2 cos (2×π/6)]
=> tan¯¹ [ 2 cos π/3 ]
=> tan¯¹ [2×1/2]
=> tan¯¹ [1]
=> π/4
Hope it helps.....✌
Answered by
8
Step-by-step explanation:
Ex 2.1 Q from ML agarwal
Hope it helps .
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