Question

Question 12 ( 2.0 marks)


An electric bulb B and a parallel plate capacitor C are connected in series to the a.c.mains as shown in the given figure. The bulb glows with some brightness.



How will the glow of the bulb be affected on introducing a dielectric slab between the plates of the capacitor? Give reasons in support of your answer.

Answer 1

Answer:

The glow of the bulb will be more brighter

Explanation:

This is because as dielectric is introduced it increases the value of capacitance and hence forth capacitance is directly proportional to the voltage.

Answer 2

The glow of bulb will increase on introducing a dielectric slab between the plates of the capacitor.

Explanation:

On introducing a dielectric slab between the plates of the capacitor there will occur an increase in its capacitance. Therefore, there will occur a decrease in the potential drop across the capacitor (as V = $\frac{Q}{C}$).

This is because both the bulb and capacitor are connected in series. As a result, the brightness of bulb will increase.

Learn more about potential drop:

https://brainly.in/question/7999160

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