Question 12:
A ball of mass 4.8kg projected upward from ground, it reaches its maximum height after 18s.
Calculate its initial velocity (take g = 10ms 2)
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Answer:
GIVEN:
Mass=4.8kg
t=18s
a=-10m/s²
v=0m/s
Find:
u=?
Explanation:
v=u+at
0=u+10×18
0=u+180
u=-180
.•. u= -180m/s
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