Question 12 answer pls
Answers
Answer:
↫↫↫↫↫ нєу ↬↬↬↬↬
Step-by-step explanation:
Given diameter of the circular pipe = 2 cm
So, the radius of the circular pipe = 2/2 = 1 cm
Height of the circular pipe = 0.7 m = 0.7*100 = 70 cm
Now, volume of the water flows in 1 second = πr2 h
= 3.142*12 *70
= 3.142 * 70
Volume of the water flows in 1/2 hours = 3.142 * 70*30*60
Now, volume of the water flows = Volume of the cylinder
=> 3.142 * 70*30*60 = πr2 h
=> 3.142 * 70*30*60 = 3.142*(40)2 h
=> 70*30*60 = 40*40* h
=> h = (70*30*60)/(40*40)
=> h = (70*3*6)/(4*4)
=> h = 1260/16
=> h = 78.85 cm
So, the level of water rise in the tank in half an hour is 78.75 cm
Answer:
78.75 cm
Step-by-step explanation:
Given,Internal diameter of the pipe = 2 cm.
Then,Internal radius of the pipe = 1 cm.
∴ Rate of water flow = 0.7 m/sec = 70 cm/sec.
Volume of water flows in 1 sec = πr²h
= (22/7) * (1)² * 70
= 220 cm³.
Volume of water flows in half an hour(30 minutes)
= 220 * 30 * 60
= 396000 cm³.
Now,
Given that radius of base is 40 cm.
Let the water level rise to height h metres in 30 minutes of base radius 40 cm.
∴ Volume of water added in it = Volume of water flows in 30 minutes.
πr²h = 396000 cm³
⇒ (22/7) * (40)² * h = 396000
⇒ 35200 * h = 396000 * 7
⇒ 35200 * h = 2772000
⇒ h = 78.75 cm.
Therefore, Level of water rises 78.75 cm in half an hour.
Hope it helps!