Question

Question 12: Find the value of the given expression: sin theta x cos(90° - theta) + tan theta x cot (90° - theta).​

Answer 1

Answer:

sin theta x cos(90° - theta) + tan theta x cot (90° - theta).

sin theta × sin theta+ tan theta × tan theta

sin^2 theta + tan^ 2 theta

Step-by-step explanation:

hope it helps

Answer 2

$\huge\star{\mathbb\orange{A}\mathbb\blue{N} \mathbb\purple{S}\mathbb\pink W}\mathbb\green{E}\mathbb\red{R}\star$

$\bold{\boxed{\pink{Sinθ×cos(90⁰- θ)+tanθ×cot(90⁰- θ)}}}$

$\bold{\boxed{\pink{= sinθ×sinθ+tanθ×tanθ}}}$

$\bold{\boxed{\pink{=sin² θ+tan² θ}}}$