Question

question:
1234567890​

Answer 1

Answer:

64

Explanation:

=> Let the unit digit be y & tens digits be x

=> Original number = ( 10x + y )

=> After interchanging the digits

=> New number = ( 10y + x )

=> ( 10x + y ) + ( 10y + x ) = 110

=> 11y + 11x = 110

=> 11 ( x + y ) = 110

=> x + y = 110 / 11

=> x + y = 10............(1)

=> x = 10 - y.............(2)

=> ( 10 x + y ) - 10 = 4 + 5 ( x + y )

=> ( 10 x + y ) - 10 = 4 + 5 ( 10 )

=> ( 10 x + y ) = 4 + 50 + 10

=> ( 10 x + y ) = 64

=> 10 ( 10 - y ) + y = 64

=> 100 - 10y + y = 64

=> 100 - 9y = 64

=> -9y = 64 - 600

=> -9y = -36

=> y = 36/9 = 4

=> y = 4

=> Putting the value of y in equation 2

=> x = 10 - y

=> x = 10 - 4

=> x = 6

Hence, the first number is 6 and second number is 4.

Original number is 10 x + y = 10 × 6 + 4 = 60 + 4 = 64

I hope this will help you dear..

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