Question

Question 126:
A wastewater sample has COD of 1 g/L of which 80% is the BOD. During partial aerobic oxidation
only 200 mg of COD was converted to CO2 and H20. The remaining BOD (mg/L) is:
Answers :
1. 800
2. 200
3. 600
4. 1000

Answer 1

Answer:

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Explanation:

the answer is

1000

Answer 2

Explanation:

80℅ of COD in 1g/l

Then, 80% of 1000mg

= 800

Due to partial oxidation of COD into CO2 and H2O

Then the remaining is= 800-200

Answer =600