Question

"Question 13 Find and correct the errors in the statement: (2a + 3b) (a − b) = 2a^2 − 3b^2

Class 8 Factorisation Page 229"

Answer 1

Common errors we done by solving algebraical expression and equation:

 
Error 1
Coefficient 1 of a term is usually not written. So we often ignores that. But while adding like terms, we should include it in the sum.

 
Error 2
When we multiply the expression enclosed in a bracket by a constant (or a variable) outside, we usually applied the multiplication to first term only. This is wrong calculation. Each term of the expression has to be multiplied by the constant (or the variable).

 
Error 3
when we square a monomial, we usually ignored the   numerical coefficient. This is wrong method. The   numerical coefficient and each factor has to be squared.

 
Error 4
when we square a binomial, we usually do not apply the proper identity. This is wrong approach. The right identity should be used.

Error 5

While dividing a polynomial by a monomial, We usually don’t divide each term of  the polynomial in the numerator by the monomial in the denominator.

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Solution:

(2a + 3b) (a − b) = 2a² − 3b²


LHS= (2a + 3b) (a - b)

=2a² -2ab+3ab-3b²

=2a² +ab-3b²

RHS = 2a² - 3b²

LHS≠ RHS

Correct statement 

(2a + 3b) (a - b)=2a² +ab-3b²

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Hope this will help you...

Answer 2

Answer:

(2a + 3b) (a − b) = 2a² − 3b²

LHS= (2a + 3b) (a - b)

=2a² -2ab+3ab-3b²

=2a² +ab-3b²

RHS = 2a² - 3b²

LHS≠ RHS

 (2a + 3b) (a - b)=2a² +ab-3b²

Step-by-step explanation:

Hope its helpful