Question 13 Solve the given inequality for real x: 2(2x + 3) – 10 < 6 (x – 2)
Class X1 - Maths -Linear Inequalities Page 122
Answers
Answered by
3
Heya buddy !!!
Here's the answer
2(2x + 3) – 10 < 6 (x – 2)
4x + 6 - 10 < 6x - 12
4x - 4 < 6x - 12
12 - 4 < 6x - 4x
2x > 8
x > 4
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer
2(2x + 3) – 10 < 6 (x – 2)
4x + 6 - 10 < 6x - 12
4x - 4 < 6x - 12
12 - 4 < 6x - 4x
2x > 8
x > 4
★★ HOPE THAT HELPS ☺️ ★★
Answered by
2
Hi ,
2(2x + 3 ) - 10 < 6 ( x - 2 )
Divide each term with 2 ,
2x + 3 - 5 < 3 ( x - 2 )
2x - 2 < 3x - 6
-2x + 2x - 2 < -2x + 3x - 6
-2 < x - 6
6 - 2 < x - 6 +6
4 < x
Therefore ,
x > 4
I hope this helps you.
:)
2(2x + 3 ) - 10 < 6 ( x - 2 )
Divide each term with 2 ,
2x + 3 - 5 < 3 ( x - 2 )
2x - 2 < 3x - 6
-2x + 2x - 2 < -2x + 3x - 6
-2 < x - 6
6 - 2 < x - 6 +6
4 < x
Therefore ,
x > 4
I hope this helps you.
:)
Similar questions