Question

Question 13.
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Answer 1

Answer:

»» 0.75 S ««

Explanation:

»» GIVEN ««

» NO. OF OSCILLATION OF THE PENDULUM = 80

» TIME TAKEN - 1 MIN = 60 SEC.

»» TO FIND ««

» THE FREQUENCY AND TIME PERIOD OF THE PENDULUM

»» SOLUTION ««

» THE FREQUENCY OF PENDULUM = NO. OF OSCILLATION / TIME TAKEN

$f = \frac{80}{60}$

» F = 1.33 Hz

» THE TIME PERIOD OF PENDULUM = 1 / FREQUENCY

» T = 1/ 1.33

» T = 0.75 S

SO, THE FREQUENCY OF THE PENDULUM OF 1.33 Hz AND THE TIME PERIOD OF THE PENDULUM IS 0.75 S .

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Answer 2

Answer:

3.Given

Number of Oscillations, N=40

Time t=1min

Frequency f=tN=6040=0.667Hz

Time period,T=f1=1.5sec

Hence, frequency is 0.667Hz and time period is 1.5sec