Question

Question 14:
A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω. How much current would flow through the 12 Ω resistor ?

Lakhmir Singh Physics Class 10

Answer 1

==============ⓢⓦⓘⓖⓨ

$\bold\red{hello...frd\:swigy\:here}$

$\bold\green{Your\:Answer:--}$

Total resistance of resistors when connected in series is given by

= 1 + 2 + 3 + 4 + 5

= 0.2 Ω+ 0.3 Ω+ 0.4 Ω+ 0.5 Ω+ 12 Ω = 13.4 Ω

According to Ohm’s law,

V = IR

I =V/R

I = 9 /13.4 = 0.67

▶▶There is no current division occurring in a series circuit.

So, the current through the 12 Ω resistor will be same as 0.67 A.

I hope, this will help you___❤❤

Thank you

✿┅═══❁✿ $\bold\green{BeHappY}$ ✿❁═══┅✿

Answer 2

Answer:

It is the correct answer.

Step-by-step explanation:

Hope this attachment helps you.