Question

Question 14
Compare the power used in the 2 Ω resistor in each of the following circuits
(i) a 6 V battery in series with 1 Ω and 2 Ω resistors, and
(ii) a 4 V battery in parallel with 12 Ω and 2 Ω resistors.
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Answer 1

Answer:

Solution:

Solution:(i) The circuit diagram is shown in figure.

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3Ω

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3ΩPotential difference, V = 6 V

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3ΩPotential difference, V = 6 VNCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3ΩPotential difference, V = 6 VNCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14Power used in 2Ω resistor = I2R = (2)2 x 2 = 8 W

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3ΩPotential difference, V = 6 VNCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14Power used in 2Ω resistor = I2R = (2)2 x 2 = 8 W(ii) The circuit diagram for this case is shown :

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3ΩPotential difference, V = 6 VNCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14Power used in 2Ω resistor = I2R = (2)2 x 2 = 8 W(ii) The circuit diagram for this case is shown :Power used in 2 resistor = v2R =422 = 8 W.

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3ΩPotential difference, V = 6 VNCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14Power used in 2Ω resistor = I2R = (2)2 x 2 = 8 W(ii) The circuit diagram for this case is shown :Power used in 2 resistor = v2R =422 = 8 W.NCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14.1

Solution:(i) The circuit diagram is shown in figure.Total resistance, R = 1Ω + 2Ω = 3ΩPotential difference, V = 6 VNCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14Power used in 2Ω resistor = I2R = (2)2 x 2 = 8 W(ii) The circuit diagram for this case is shown :Power used in 2 resistor = v2R =422 = 8 W.NCERT Solutions for Class 10 Science Chapter 12 Electricity Chapter End Questions Q14.1[ ∵ Current is different for different resistors in parallel combination.]