Question

Question 14.
Find the value of (cosec² θ – l).tan²θ​

Answer 1

this a solution

the is 0 ....

Answer 2

Given-

$( {cosec}^{2} θ \: - 1). {tan}^{2}θ$

To find-

Simplified value

Solution-

We know that,

1+ cot²θ= cosec²θ

i.e. cot²θ = cosec²θ-1 --------------(1 )

$( {cosec}^{2} θ - 1). {tan}^{2} θ \\ = {cot}^{2} θ. {tan}^{2} θ \: \: \: \: \: \: \: \: \: \: (from \: 1) \\ = \frac{1}{ {tan}^{2} θ} \times {tan}^{2} θ \\ = 1$