Question 14: If, sin (sin¯¹ 1/5 + cos¯¹ x) = 1, then find the value of x.
Class 12 - Math - Inverse Trigonometric Functions
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sin(sin-¹ 1/5 + cos-¹x ) = 1
=> sin-¹ 1/5 + cos-¹x = sin-¹ (1)
= sin-¹ 1/5 = π/2-cos-¹x
= sin-¹ 1/5 = sin-¹ x
=> x = 1/5
=> sin-¹ 1/5 + cos-¹x = sin-¹ (1)
= sin-¹ 1/5 = π/2-cos-¹x
= sin-¹ 1/5 = sin-¹ x
=> x = 1/5
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