Question

Question 14. In the figure, all four outer circles are of same
ngure, all four outer circles are of same radius r, and then the radius of inner circle
is​

Answer 1

Answer:

Root 2 is the radius

Step-by-step explanation:

Side of square = 2r ( radius of the two circle)

Now,

Using Pythagoras theorem we can find out the length of diagonal.

Diagonal =

$\sqrt{ {2r}^{2} + {2r}^{2} }$

=

$\sqrt{8 {r}^{2} }$

=

$2 r\sqrt{2}$

Now to find the radius of inner circle =diagonal - 2(radius)

=

$2r \sqrt{2 } - 2r = \sqrt{2}$